12c^2-12c+3=0

Solution for 12c^2-12c+3=0 equation:

Simplifying
12c2 + -12c + 3 = 0

Reorder the terms:
3 + -12c + 12c2 = 0

Solving
3 + -12c + 12c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '3'.
3(1 + -4c + 4c2) = 0

Factor a trinomial.
3((1 + -2c)(1 + -2c)) = 0

Ignore the factor 3.
Subproblem 1
Set the factor '(1 + -2c)' equal to zero and attempt to solve:

Simplifying
1 + -2c = 0

Solving
1 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2c = 0 + -1
-2c = 0 + -1

Combine like terms: 0 + -1 = -1
-2c = -1

Divide each side by '-2'.
c = 0.5

Simplifying
c = 0.5
Subproblem 2
Set the factor '(1 + -2c)' equal to zero and attempt to solve:

Simplifying
1 + -2c = 0

Solving
1 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2c = 0 + -1
-2c = 0 + -1

Combine like terms: 0 + -1 = -1
-2c = -1

Divide each side by '-2'.
c = 0.5

Simplifying
c = 0.5
Solution
c = {0.5, 0.5}